2=4(1[v+4]1)-6v

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Solution for 2=4(1[v+4]1)-6v equation:


Simplifying
2 = 4(1[v + 4] * 1) + -6v

Reorder the terms:
2 = 4(1[4 + v] * 1) + -6v

Reorder the terms for easier multiplication:
2 = 4(1 * 1[4 + v]) + -6v

Multiply 1 * 1
2 = 4(1[4 + v]) + -6v
2 = 4([4 * 1 + v * 1]) + -6v
2 = 4([4 + 1v]) + -6v
2 = (4 * 4 + 1v * 4) + -6v
2 = (16 + 4v) + -6v

Combine like terms: 4v + -6v = -2v
2 = 16 + -2v

Solving
2 = 16 + -2v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '2v' to each side of the equation.
2 + 2v = 16 + -2v + 2v

Combine like terms: -2v + 2v = 0
2 + 2v = 16 + 0
2 + 2v = 16

Add '-2' to each side of the equation.
2 + -2 + 2v = 16 + -2

Combine like terms: 2 + -2 = 0
0 + 2v = 16 + -2
2v = 16 + -2

Combine like terms: 16 + -2 = 14
2v = 14

Divide each side by '2'.
v = 7

Simplifying
v = 7

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